in reply to Returning multiple Hash references from a sub()
Or just work with hashrefs:my @out = ParseForExpDB2Param(@params); my %ExpValHash4 = %{$out[0]}; my %ExpValHash5 = %{$out[1]}; my %ExpValHash6 = %{$out[2]};
my ($ExpValHash4, $ExpValHash5, $ExpValHash6) = ParseForExpDB2Param(@p +arams);
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