Re: [Perl 6] Re: Passing two arrays to a subroutine

Well I liked the reply from moritz, it was a bit of fun and that's good (I gave him a ribbing on a /msg though).

Back to the question. Correct me if I'm wrong (I know you will), but isn't the Perl 6 solution using references as well? To quote Apocalyse 6:
"All positional parameters regardless of their type are considered scalars, and imply scalar context for the actual arguments. If you pass an array or hash to such a parameter, it will actually pass a reference to the array or hash, just as if you'd backslashed the actual argument.

So Perl 6 still passes references, its just that the syntax no longer requires the \.

Comment on Re: [Perl 6] Re: Passing two arrays to a subroutine

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Re^2: [Perl 6] Re: Passing two arrays to a subroutine by moritz (Cardinal) on Sep 29, 2010 at 08:36 UTC
To quote Apocalyse 6 Please note that the Apocalypses are mostly historical documents. S06 is what you should consider. but isn't the Perl 6 solution using references as well? Yes. Under the hood, every argument passing uses references, unless the parameter is decorated with the `is copy` trait. Unlike in Perl 5, these references are write protected by default. So Perl 6 still passes references, its just that the syntax no longer requires the \. Not only the backslash, but also the dereferencing inside the subroutine. Since (nearly) everything in Perl 6 is a reference, references are transparent, and don't require special syntax on either side. Perl 6 - links to (nearly) everything that is Perl 6.	[reply] [d/l]
Re^2: [Perl 6] Re: Passing two arrays to a subroutine by chromatic (Archbishop) on Sep 28, 2010 at 20:34 UTC
So Perl 6 still passes references, its just that the syntax no longer requires the \. It's slightly more accurate to say (from the language design point of view) that Perl 6 passes these values by reference. Unfortunately, then things get complex with other parameter traits and so on and so forth.	[reply]