Re^5: Named Captures

Not quite.

() = 'abc' =~ /(?<a>a)|(?<f>f)/ and do {say for keys %-};
__END__
a
f
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%- will have a key for every named capture in the pattern, whether that capture was involved in the match or not.

Comment on Re^5: Named Captures Download Code

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Re^6: Named Captures by BrowserUk (Patriarch) on Oct 06, 2010 at 15:12 UTC
Yes. Hence the "sort of". For my purpose, I just needed to ensure that lots of things got captured, I was never going to do anything with them. I was trying to heavily exercise both named captures and alternations in the hope of reproducing a memory leak.	[reply]