in reply to Pass sub reference
#!/usr/bin/perl sub xxx { my $x1 = shift; my $x2 = shift; print "$x1, $x2\n"; } sub yyy { my $func = shift; $func->(@_) } yyy( \&xxx, "foo", 42 ); # \&xxx is the sub reference.
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Re^2: Pass sub reference
by Anonymous Monk on Oct 28, 2010 at 17:16 UTC | |
by AnomalousMonk (Archbishop) on Oct 29, 2010 at 00:59 UTC |