in reply to Passing three arrays to a subroutine

Possibly your prototyping is wrong, since you are passing in arrayref's, not actual arrays. 
sub myCurveX($$$$$)

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But why even use prototypes in the sub? 

#$my_exp = myCurveX(\@my_arx,\@my_ary,\@my_arz,$my_v1,$my_v2);

#sub myCurveX(){  # thanks to [jwkrahn] (below) for pointing out my co
+de sloppiness
sub myCurveX{  #correct.... no ()
 my ($arrayref1, $arrayref2,$arrayref3, $v1, $v2) = @_;
$arrayref1->[0] = 1;  #sets first element of @my_arx to 1

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I'm not really a human, but I play one on earth.
Old Perl Programmer Haiku ................... flash japh

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Re^2: Passing three arrays to a subroutine
by jwkrahn (Abbot) on Nov 09, 2010 at 18:27 UTC
    But why even use prototypes in the sub? 
    $my_exp = myCurveX(\@my_arx,\@my_ary,\@my_arz,$my_v1,$my_v2);

sub myCurveX(){
 my ($arrayref1, $arrayref2,$arrayref3, $v1, $v2) = @_;

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    You say "why even use prototypes" and then you use a prototype that says accept zero arguments, but the next line says to accept five arguments?

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[d/l]
      Well you have to read in values into the sub somehow, unless you use global variables. How else would he do it?
      I'm not really a human, but I play one on earth.
      Old Perl Programmer Haiku ................... flash japh
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        You missed the point. The problem isn't that you accept five arguments; the problem is that you use a prototype that says "accept zero arguments". There's also the matter that you use a prototype after saying there's no reason to use prototypes here.
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