Re: Adding Numbers

When I run your program, and enter the numbers '3' and '7', the output I get is:

44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444
44444444444444444444444444444444444444444444444444444444444444444444444444444444

At that point I pressed Control-C to interupt the program.

Is that what you got? Is that the result you were expecting? In what way did my experience differ from your expectations?

As Occam said: Entia non sunt multiplicanda praeter necessitatem.

Comment on Re: Adding Numbers

Replies are listed 'Best First'.
Re^2: Adding Numbers by NastyPenguin (Initiate) on Nov 21, 2010 at 06:17 UTC
the output i'm looking for, given '3' and '7' is 3,4,5,6,7	[reply]
Re^3: Adding Numbers by GrandFather (Saint) on Nov 21, 2010 at 06:26 UTC
`my @range = 3 .. 7;` [download] True laziness is hard work	[reply] [d/l]
Re^3: Adding Numbers by TomDLux (Vicar) on Nov 22, 2010 at 01:22 UTC
You want the result to be '3 4 5 6 7' and the actual result is '4 4 4 4 4 ...'. So there's two things wrong, the first is that you start at '$ipa + 1' rather than at '$ipa'. What's the second thing that's wrong? As Occam said: Entia non sunt multiplicanda praeter necessitatem.	[reply]