Eh, perhaps on *your* system, but look at this:

    $ perl -le 'print \\///\\\//'
    1.00000026558336981
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What the result of \\///\\\// is depends on how memory is alloced. It'll depend on your malloc (which could be the Perl supplied, or the system one, depending on how Perl was build); it'll hand out addresses using some algorithm, based on various factors. Don't assume that when you run it once on your system, it will be the same universally.

-- Abigail