Re: regexp look behind?

keep track of your last line's match. If you'll wrap your regex in parenthesis like so if (/(cache|disk-)/i), you can assign the match to a variable, like so $lastmatch = $1;, then each pass through your loop, you then can print "\n" if ($lastmatch ne $1 and "disk-" eq lc $1);

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Re^2: regexp look behind? by dbs (Sexton) on Nov 30, 2010 at 19:24 UTC
thanks but no cigar! I would like the output to be `cache,23778,0.0,0,0.0,0,0.0,0.0,0.00 cache,205,0.0,0,0.0,0,0.0,0.0,0.00 "newline here" DISK-UTIL-PEAK-HIGH:,54.3,DISK-UTIL:,2.5 "newline here" PROC-Name,PID,PYS-IO-RATE,READs,READ-RATE,WRITEs cache,26094,0.9,1,0.9,0,0.0,0.0,0.00 cache,16046,0.0,0,0.0,0,0.0,0.0,0.00 cache,3848,0.0,0,0.0,0,0.0,0.0,0.00 cache,23778,0.0,0,0.0,0,0.0,0.0,0.00 cache,205,0.0,0,0.0,0,0.0,0.0,0.00 "newline here" DISK-UTIL-PEAK-HIGH:,54.3,DISK-UTIL:,3 ### last line ###` [download]	[reply] [d/l]
Re^3: regexp look behind? by AnomalousMonk (Archbishop) on Dec 01, 2010 at 01:25 UTC
No, thank you for finally clarifying just what you want the output to be!	[reply]
Re^4: regexp look behind? by raybies (Chaplain) on Dec 01, 2010 at 13:21 UTC
Yes, thanks for clarifying the output. that was something I could not parse from the discription given in the original problem. So take my original suggestion and instead of the if statement looking like I suggested make the print portion be `print "\n$_\n\n" if (same as code given)`.	[reply] [d/l]