array of arrays

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

hello

my @arrays = ([2,4,6],[8,9,5],[1,2,3]);
print $arrays[1][2];
my @secondArr = $arrays[1];
print "@secondArr";
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the output of the first print is 5
now i want to assign all the second array to a variable
but i can't do that without going to the elements of the second array one by one, certainly there is a syntax for that. i want @secondArr to contain (8,9,5) so the second print will print 8,9,5
regards

Comment on array of arrays Download Code

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Re: array of arrays by moritz (Cardinal) on Dec 06, 2010 at 09:58 UTC
suhailck has shown how to do it; let me add the information of where to find that in the docs: perlreftut gently introduces references and also dereferncing. perllol specifically talks about arrays of arrays, perldsc about nested data structures in general. Perl 6 - second systems done right	[reply]
Re^2: array of arrays by AnomalousMonk (Archbishop) on Dec 06, 2010 at 13:09 UTC
Don't forget the gory details: perlref.	[reply]
Re: array of arrays by suhailck (Friar) on Dec 06, 2010 at 09:53 UTC
`perl -le '@arrays = ([2,4,6],[8,9,5],[1,2,3]); @secondArr=@{$arrays[1]}; print "@secondArr"' 8 9 5` [download]	[reply] [d/l]
Re: array of arrays by 7stud (Deacon) on Dec 07, 2010 at 03:03 UTC
This line: `my @arrays = ([2,4,6],[8,9,5],[1,2,3]);` creates an array of references, like this: `@arrays = ($ref1, $ref2, $ref3);` Your array access here: `print $arrays[1][2];` is shorthand for: `$arrays[1]->[2]` [download] which is shorthand for: `@{$arrays[1]} [2]` [download] Because the elements of @arrays are references, in order for you to get the second reference, you would write this: `$arrays[1]` [download] And to convert a reference to the actual array (i.e. dereference the reference), you would write this: `@{$arrays[1]}` [download] Braces are used to turn a reference into the thing it references.	[reply] [d/l] [select]