in reply to Re: (tye)Re: Regular expression
in thread Regular expression
produces:#!/usr/bin/perl -w $_= "193287461528"; "0 but true" while s/(\d)(\d\d\d)(\D|$)/$1,$2$3/; print;
Useless use of a constant in void context at warn.pl line 3. 193,287,461,528
because the "0 but true" doesn't yet have a numeric value so the "is 0 or 1" test doesn't even get attempted.
To get "0 but true" to work as an "unwarned useless constant", you have to jump through some interesting hoops:
produces#!/usr/bin/perl -w $_= "193287461528"; sub zero() { "0 but true" } BEGIN { if( @ARGV ) { eval '0+zero'; } } zero while s/(\d)(\d\d\d)(\D|$)/$1,$2$3/; print;
The "()" in "sub zero()" is required for Perl to compile uses of "zero" as a constant (instead of as a subroutine call). The "0+zero" causes Perl to cache a numeric value for the "zero" constant. But you'll note that this caching is done at compile time so I have to use stringy eval to prevent it from happening when I don't want it to. But stringy eval also prevents it from happening at compile time even if that code gets run so I have to use a BEGIN block to get conditional compile-time behavior.$ perl warn.pl Useless use of a constant in void context at warn.pl line 9. 193,287,461,528 $ perl warn.pl x 193,287,461,528
So, how to use "0 but true" as a unwarned useless constant can be reduced to:
- tye (but my friends call me "Tye")#!/usr/bin/perl -w $_= "193287461528"; sub zero() { "0 but true" } zero while s/(\d)(\d\d\d)(\D|$)/$1,$2$3/; print; my $x= 0+zero;
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