entropy has asked for the wisdom of the Perl Monks concerning the following question:

$a=*{}; # doesn't like that $a=*{''}; # that seems like a completely different glob! $a=*; # oops! - the * eats the ; $a=(*); # doesn't like that either

Replies are listed 'Best First'.
Re: What does ($*) do, and how is it different than (${*{''}})?
by japhy (Canon) on Jun 12, 2001 at 04:10 UTC
    $a = **;

    Originally posted as a Categorized Answer.

Re: How do I get the * glob, what is $*, and what is *{''}?
by japhy (Canon) on Jun 12, 2001 at 04:11 UTC
    $a = **;

    $* is a deprecated variable used for regexes.

      Wow, that clears it up.
      I had done '$a=*' in the debugger, which causes 'print $a' to show it as a glob (*main::;). I suppose the trick is that the debugger took it upon itself to add a couple of semi-colons in there, making it '$a=*;;' or in other words '$a=*{";"};'.