Re^3: If condition failing..

I didn't follow the discussion in the original thread, so maybe I'm missing something... but why don't you store the version as the value of the hash entries?

while (<IN>) {  # first list
    next unless ( m:(.+?)#(\d+)$: );
    $pathname_versions{$1} = $2;
}
[download]

In this case you could later simply do (where $pathname_versions{$1} retrieves the corresponding version from the first list)

while (<IN>) {  # second list
    next unless ( m:(.+?)#(\d+)$: );
    ...
    if ( $pathname_versions{$1} < $2 ) { ...
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Re^4: If condition failing.. by perl_mystery (Beadle) on Dec 13, 2010 at 01:49 UTC
Actually I want the other way like below,but if i use it i am getting the below error. `if ( $pathname_versions{$1} > $2) { #if the version in list2 i +s less than version for the same path in list1 print "IN\n"; }` [download] Can't use string ("6") as a HASH ref while "strict refs" in use at orphan_overwrite.pl line 30, <IN> line 28	[reply] [d/l]
Re^5: If condition failing.. by Anonyrnous Monk (Hermit) on Dec 13, 2010 at 02:08 UTC
`Can't use string ("6") as a HASH ref` This is probably because somewhere else you still have `$pathname_versions{$1}{$2}`. So, if `$pathname_versions{$1}` is now "6", for example, the `{$2}` would be trying to dereference the value "6", i.e. `"6"->{$2}`, which doesn't make much sense...	[reply] [d/l] [select]