in reply to Re^2: XML::Simple, XMLOut() question
in thread XML::Simple, XMLOut() question

You need not loop. Following would suffice

$x->{user}->{favorites} = {item => $x->{user}->{favorites}};

where $x is your original structure


-- Regards - Samar

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Re^4: XML::Simple, XMLOut() question
by duesouth (Initiate) on Dec 15, 2010 at 16:17 UTC
    Many thanks, that's done the trick.
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