Re^4: Question on Regex grouping

People who dislike list slicing should avoid scripting languages, especially Perl. It's FALSE that you don't know whether there was a match with m//g because the created list is simply empty. Also, the GOATSE ( =()=) recreates the right context if that's an issue.

Take this code: $x = "a123b345c7865d87"; 
  @L = ($x =~ /a-z/g)1,3; print "@L"; ## Prins b d 
  @X = ($x =~ /#/g)[1,3]; 
  print (defined(@X) ? "YES" : "NO";
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It prints NO ... therefore, JavaFan, your assertions are FALSE and FALSE. TenThouPerlStudents

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Re^5: Question on Regex grouping by JavaFan (Canon) on Dec 22, 2010 at 11:44 UTC
People who dislike list slicing should avoid scripting languages, especially Perl. Really? Just because I find list slices to avoid using $1 ugly? What else? People who don't like goto should avoid Perl? People who don't like m?? should avoid Perl? People who don't like code without warnings or strict? `@X = ($x =~ /#/g)[1,3];` Ain't working. Sure, for the given pattern, it works. Now, let's change the pattern a little, shall we: `my $x = "1234"; my @X = ($x =~ /(#)?/)[1,3]; say scalar @X; # defined(@X) is deprecated say "Matched" if $x =~ /(#)?/; __END__ 0 Matched` [download] So, @X is empty, yet the pattern matches. It prints NO ... therefore, JavaFan, your assertions are FALSE and FALSE. When I say "it doesn't always work", a single example where it does work isn't a contradiction. Note also that Marshall wasn't doing it your way anyway, he put the list slice in scalar context.	[reply] [d/l] [select]
Re^6: Question on Regex grouping by TenThouPerlStudents (Initiate) on Dec 22, 2010 at 18:39 UTC
Even more "deprecated" is a "pattern" like (#)? where: a) There's no reason for the parens, and b) Where the pattern is ALWAYS true because you CANNOT FAIL to match zero instances of ANYTHING!!! I find your "refutation" bizarre!! Since when is asking if ANY type of variable "deprecated"???	[reply]