Re^5: [NOT] How would you decode this?

Ah right, I was thinking about the cutoff point being at 2^24 and that is a power of two. Really self-evident ;-)) Doh

Comment on Re^5: [NOT] How would you decode this?

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Re^6: [NOT] How would you decode this? by LanX (Saint) on Dec 28, 2010 at 22:24 UTC
Since at the end you have to use an AND anyway to cut off the 2 flag-bits you could use a negative offset of 8 bits and mask 10 bits of a 2**5=32 bit vec without loss of speed! `Flags 01234567\|FF\|ddddddddddddddddddddd 32 bit Vector -8 bits \| \| 22 bits Data 00000000\|00\|111111111111111111111 Mask` [download] Cheers Rolf	[reply] [d/l]