Re: comparison with bitwise operators (sarcasm)

if(  3-2 == abs( 3+2 - 2*$var )  ) {
    # q-:
}
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If you have 3 values, it takes slightly more work:

if(  not $var**3 - 12*$var**2 + 41*$var - 42  ) {
    # $var is 2, 3, or 7
}
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For the specific case of 2 and 3:

if(  3 == ( $var | 1 )  ) {
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Re^2: comparison with bitwise operators (horror) by ikegami (Patriarch) on Jan 13, 2011 at 22:04 UTC
That reminds me of the time I had to debug this old BASIC game that used hundreds of expressions like `y = 4 - (x > 3) * 2` [download] to achieve `$y = $x > 3 ? 6 : 4;` [download] Some assignments even had more than one such conditional per line. It was hell. (True was -1)	[reply] [d/l] [select]