Re: using / accessing nested hash/array references

These:

    @results = &get_list();
    $hostresults[0] = &get_list();
[download]

are not equivalent. You have encountered a context issue, the first line above is list context, the second is scalar, in other words, $hostresults[0] is not an array as I think you are expecting. I think what you would want to do is change the second line to something like:

$hostresults[$i] = \@results;
[download]

Then $hostresults[0] is a reference to your first data set.

You might want to look at perldsc and perlref

Comment on Re: using / accessing nested hash/array references Select or Download Code

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Re^2: using / accessing nested hash/array references by tspfwj (Initiate) on Jan 18, 2011 at 23:40 UTC
I changed the line to `$hostresults[0] = \@{&get_list()};` [download] and I am still receiving the scalar error. I have experimented with initializing like `my @hostresults = (\@result1,\@result2); #or my @hostresults = (@result1,@result2);` [download] but I still received errors. My attempts would have been with the same context though. The right side sub returns the array of hash references which is why I left in the line above in my original example. My hope was to show what was happening outside of my context or syntax errors. Thank you	[reply] [d/l] [select]
Re^3: using / accessing nested hash/array references by state-o-dis-array (Hermit) on Jan 19, 2011 at 00:03 UTC
Sorry, I was kind of hoping that having changed how you are assigning to $hostresults[0] that you might take that as a clue to look at how you are accessing it. Anonyrnous Monk provides a valuable suggestion in referring you to Data::Dumper. Also, have you taken time to check out the links I provided? I think that they will be helpful to you.	[reply]