Re: while () vs. while (1)

I've known about this behaviour for a long time. I think it's because while (EXPR) { } is treated as if it were for (;EXPR;) { }. And for (;;) { } is, just as in C, an infinite loop.

Note that Deparse turns both while () {} and for (;;) {} into while (1) {}.

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Re^2: while () vs. while (1) (trivia) by ikegami (Patriarch) on Jan 24, 2011 at 16:21 UTC
Note that Deparse turns both while () {} and for (;;) {} into while (1) {}. All three are identical in the optree, but it's closer to `while () {}`. No "1" constant exists. All C-style for loops, while loops and bare loops ("`{ ... }`") are implemented using the same loop op. The condition of "`while (1)`" is completely optimised away.	[reply] [d/l] [select]