Re^2: Regex failing when the line starts with "./"

I'm trying to wrap my head around this and it's not coming together.
Wouldn't (?:\.\\|\./) mean "full stop, then either backslash or dot, then forward slash"?
I have no time to test this now, but it seems to me that the correct regex would be:
$line =~ m{(?:\.\\)|(?:\./)(.*);};
with grouping on either side of the |. Or does a | placed within grouping parentheses always match the entire first/second half of the grouping?

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Re^3: Regex failing when the line starts with "./" by Anonymous Monk on Feb 03, 2011 at 12:33 UTC
Wouldn't `(?:\.\\\|\./)` mean "full stop, then either backslash or dot, then forward slash"? ... Or does a \| placed within grouping parentheses always match the entire first/second half of the grouping? It is second case: `[.\\]` is one group of regex, `[./]` is the other. To match per your first query, regex would be `qr{[.] (?: \\ \| . ) /}x` (which I would rather write as `qr{[.] [.\\] /}x` but that is besides the point).	[reply] [d/l] [select]
Re^4: Regex failing when the line starts with "./" by Anonymous Monk on Feb 03, 2011 at 12:36 UTC
Carp! Please change ... `[.\\]` is one group of regex, `[./]` is the other ... to ... `.\\` is one group of regex, `./` is the other	[reply] [d/l] [select]
Re^5: Regex failing when the line starts with "./" by Anonymous Monk on Feb 03, 2011 at 14:07 UTC
I give up (and wish I had remembered the password).	[reply]