Re^3: Please Review First Program: Random Password Generator

you use q[ ... ] with symbols [ and ] in there. Why does that not cause a syntax error?

For the why I can only answer with a generic: because Perl's parser is (mostly :) well thought out and implemented.
I assume that the parser must be doing a maximal munch at that point.
The 'balanced quoting' facilities of Perl are one (of many) things that I really miss in other languages. They save so much mess & hassle with escaping stuff.
Mind you, I abhor their overuse in Perl--eg. q[] instead of a simple ''--almost as much as I miss them when they aren't available.
And what does that #' comment at the line end mean to you?

That's simply a crutch for my editor's less capable syntax highlighting parser. It see's the single quote embedded in the construct and starts highlighting the following text as a string constant, but doesn't stop until it sees a second single quote.
The comment prevents that erroneous highlighting from running on to subsequent lines.

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

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Re^4: Please Review First Program: Random Password Generator by ikegami (Patriarch) on Feb 05, 2011 at 05:31 UTC
perlop: "Non-bracketing delimiters use the same character fore and aft, but the four sorts of brackets (round, angle, square, curly) will all nest". `q[ ] ] # XXX q[ [ ] # XXX q[ [ ] ] # ok q[ [ ] [ ] ] # ok q[ [ [ ] ] ] # ok q( [ ) # ok q[ ( ] # ok` [download]	[reply] [d/l]