Re: Why won't say act like say when its tied?

Replies are listed 'Best First'.
Re^2: Why won't say act like say when its tied? by ELISHEVA (Prior) on Mar 07, 2011 at 17:51 UTC
print appends the value of `$\` to the end of whatever is passed to print, so if `$\="*\n"`, then `{print "hello", "\n"; }` outputs `"hello\n*\n"` not plain `"hello\n"`. That's why it is important for say to set `local $\="\n"` and not just add `"\n"` to the end of the list of things to print. Hope that helps.	[reply] [d/l] [select]
Re^3: Why won't say act like say when its tied? by Anonymous Monk on Mar 07, 2011 at 19:45 UTC
Thanks, it does. So the intended behavior for say is to write exactly what the programmer intended plus \n without side effects from punctuation variables. Good to know.	[reply]
Re^2: Why won't say act like say when its tied? by ikegami (Patriarch) on Mar 07, 2011 at 18:12 UTC
It's only done that way for tied handles. Existing tie modules had to support `say` without being changed, and changing `$\` allows that. I suppose they could have done `local $\; ->PRINT(@_); ->PRINT("\n");` [download] But if `$\` is being localised anyway, might as well do `local $\ = "\n"; ->PRINT(@_);` [download]	[reply] [d/l] [select]