in reply to Re: How to iterate through a PDL piddle?
in thread How to iterate through a PDL piddle?

Thanks @zentara. It works! I can't believe that it works though. There should be a more obvious way like  $u->list which gives an array reference. Or a custom iterator on a piddle which can replace  foreach.

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Re^3: How to iterate through a PDL piddle?
by etj (Priest) on May 26, 2022 at 14:44 UTC
    If you feel the urge to use an iterator in PDL, quite often that is a sign you could instead use "array programming" type constructs (see https://en.wikipedia.org/wiki/Array_programming), which lets all the processing be done inside the fast C loops, rather than going backwards and forwards between Perl and PDL.
Re^3: How to iterate through a PDL piddle?
by dkogan (Initiate) on Apr 22, 2011 at 07:47 UTC
    Errr..... there IS a 'list' function $u->list acts the same as $u->dog except list breaks the piddle up into individual elements while dog breaks it up into N-1-dimensional slices. In this particular case, where $u is one-dimensional, $u->list is identical to $u->dog
      • dog returns a list of PDL slices, as Dima says, so a 2,3,4 ndarray dog-ed would return 4 ndarrays each dimensioned 2,3 (and as they're "slices", updates to them would be reflected in the original ndarray)
      • list returns the ndarray flattened (so the whole thing in a single flat list) as Perl scalars, so a 2,3,4 would be a list of 24 Perl scalars
      • unpdl (as of 2.006 from 2013, as provided by the mighty Joel Berger), which returns the ndarray as an array-ref with the same (possibly nested) structure as the input ndarray.