Re: Finding only names in a dir and searching for case issues

Algorithm:

Use File::Find (Core) or File::Find::Rule (CPAN) to create a list of files.
For each file, get the basename of the file. Store the lc of the basename as a key in a hash, the value being the full file name.
If a hash key already exists, print out both full file paths.

Comment on Re: Finding only names in a dir and searching for case issues

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Re^2: Finding only names in a dir and searching for case issues by perl_mystery (Beadle) on Mar 17, 2011 at 07:53 UTC
I am not sure how this helps,for example,lets say there a file name "Data.h" in our list of files,and there is a file "foo.c" which has #include "data.h"(observe the case-sensitivty for letter "d").Now I want to print the file name and the #include line.Can anyone give a sample code or atlease suggest a correct algorithm?	[reply]
Re^3: Finding only names in a dir and searching for case issues by Neighbour (Friar) on Mar 17, 2011 at 08:06 UTC
Sounds like you're looking for functionality like this: `ls -1 \| while read filename; do grep -ir "$filename" * \| grep -v "$fil +ename" ; done` [download] (However, this is not perl :)	[reply] [d/l]
Re^4: Finding only names in a dir and searching for case issues by perl_mystery (Beadle) on Mar 17, 2011 at 08:47 UTC
Thanks for reply but that is not what I need. I have a data.txt file which contains a flat list of all the files ,now I want to grep each and every file in this data.txt in a dir(and sub dir) and print those files and the corresponding lines that has case-mismatches.Can you or anyone pls give me any sample code or an algorithm and I can try to implement in perl	[reply]