use warnings;
use strict;

my %age = (
    years  => 5,
    months => 0,
    weeks  => 2,
    days   => 0,
);

for (sort keys %age) {
    print "$_ = $age{$_}\n" if $age{$_};
}

__END__

weeks = 2
years = 5
[download]

I think I sort of get what you mean, but I'm really new to Perl, and I'm not sure if I explained exactly what I wanted to do right, or if I'm just not understanding your code.

In my head I think of a print statement that looks like...

print "You are $years years $months months $weeks weeks $days days old.";

So now if you were 28 years and 3 days old...it would only print "You are 28 years 3 days old."? Or if you were 28 years and 1 week old...it would only print "You are 28 years 1 week old." Does storing them in a hash allow me to do that?

You could still use a hash:

use warnings;
use strict;

my %age = (
    years  => 28,
    months => 0,
    weeks  => 0,
    days   => 3,
);

print 'You are ';
for (qw(years months weeks days)) {
    print "$age{$_} $_ " if $age{$_};
}
print "old.\n";

__END__

You are 28 years 3 days old.
[download]

But, an array may be simpler.

Thanks again! I really just couldn't grasp how to do that until you answered.