Re: Hex to decimal resulting in integer overflow

Your build of Perl cannot hold numbers that big (48 bits).

You could recompile your Perl to support 64-bit numbers.
You could use a module that provides arbitrary precision number (like Math::BigInt).
You could use a module that provides access to large native integers (like Math::Int64 and Math::Int128).

You could even store it in a floating point number without loss.

my $num = hex(substr(("0"x12).$hex, -12, 4)) * 2**32
    + hex(substr(("0"x12).$hex, -8));
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Update: Added mention on Math::BigInt, Math::Int64 and Math::Int128.
Update: Fixed bug. (0x12 is not the same as "0"x12!)

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Re^2: Hex to decimal resulting in integer overflow by ikegami (Patriarch) on Apr 01, 2011 at 17:55 UTC
Turns out that `hex` will actually use floating point numbers if required. The warning doesn't indicate outright failure as Isuspected; it indicate a potentional loss of precision. But it you're numbers are no more than 53 bits in size, there is no problem and you can silence the warning.	[reply] [d/l]