Re: Modifying an array of hashes

There is not problem with doing that. You are not changing the contents of the array, only the contents of hashes referenced by elements of the array.

A more Perlish way to write the loop is:

for my $person (@people) {
    if ($person->{name} eq 'Bob') {
        $person->{name} = 'Robert';    # MODIFY
        $person->{age}  = 46;          # ADD
    }
}
[download]

True laziness is hard work

Comment on Re: Modifying an array of hashes Download Code

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Re^2: Modifying an array of hashes by JavaFan (Canon) on Apr 06, 2011 at 21:24 UTC
And even more Perlish is the use of map, low precedence `and`, hash slices, and list assignment (untested): `map {$$_{name} eq 'Bob' and @{$_}{qw{name age}} = qw{Robert 42}}} @peo +ple;` [download]	[reply] [d/l] [select]
Re^3: Modifying an array of hashes by ikegami (Patriarch) on Apr 06, 2011 at 22:30 UTC
yuck!	[reply]
Re^3: Modifying an array of hashes by believer (Sexton) on Apr 11, 2011 at 13:43 UTC
Yuck indeed. This will not work because `$$_{name} eq 'Bob' and @{$_}{qw{name age}` [download] will at best evaluate to '' for non-Bobs.	[reply] [d/l]