Re: Regex: continue from previous match

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Re^2: Regex: continue from previous match by John M. Dlugosz (Monsignor) on Apr 23, 2011 at 08:02 UTC
That's what I have (no \G) and it doesn't work. Your example of an 'a' followed by any one char will not match variable length or different ways at the same position, so it's moot. Put two a's in a row in your test string and you'll see overlapping matches. `perl -E'while ("abaaxxxacxxad" =~ /a(.)/g) { say $& }'`	[reply] [d/l]
Re^3: Regex: continue from previous match by ikegami (Patriarch) on Apr 23, 2011 at 08:07 UTC
Your example of an 'a' followed by any one char will not match variable length Sure it works with variable length patterns. `while ('abxxxacdxxxae' =~ /a([^x]+)/g) { say $1; }` [download] Your example of an 'a' followed by any one char will not match [...] different ways at the same position Cause you didn't ask that. You asked about matching no earlier than `pos`. The only way to make the regex engine backtrack is to cause the match to fail. `'abcd' =~ /(.*) (?{ say $1 }) (?!)/sx` [download]	[reply] [d/l] [select]