in reply to Help me not use for($i=0;$i=$#array;$i++)...Please!

How about: 
for $i(0..$#array) {
    splice @array, $i, 1 if $array[$i] == 5;
}

[download]
Update: Got called away for dinner and didn't get a chance to finish(but it looks like others beat me anyway).

Also, it all you care about is the value of the array, i.e., not its index, you could use this: 

for (@array) { ... if $_ == 5. }

[download]

Replies are listed 'Best First'.
Re: Re: Help me not use codefor($i=0;$i=$#array;$i++)/code...Please!
by chromatic (Archbishop) on Jun 21, 2001 at 05:07 UTC
    I wouldn't use the splice construct inside of a loop iterating over the array. It'll get rid of the right elements, but it'll keep the array the same size due to autovivification at the end. (This may depend on the version of Perl.) Running under strict exposes this: 
    my @array = (0 .. 9);
$" = " ";

for my $i (0 .. $#array) {
    splice @array, $i, 1 if $array[$i] == 5;
    print "$i: @array\n";
}
print "Array is ", scalar @array, " elements long.\n";

    [download]
    Bang, uninitialized value and @array is 9 elements long at the end. Yikes.
[reply]
[d/l]
      And what's worse, if you have consequetive elements equal to 5, only of them is removed. Because the splice moves everything following one down, but the next iteration ups the counter.

      -- Abigail

[reply]
[d/l]
[select]
        If you need to splice in a loop there is an easy solution, just count down to zero rather than counting up in the normal way.

        -- iakobski

[reply]

In Section Seekers of Perl Wisdom