Re: using functions within regex

I Tried to use a function in a replace regex

The second half of the substitution operator (s///) is just a string, not a regex.

One way to do it is:

$t =~ s/$somePattern/@{[ some_function($1) ]}/g;
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Re^2: using functions within regex by davido (Cardinal) on May 04, 2011 at 05:45 UTC
That would be the perfect way, if the /e modifier wasn't specifically designed to provide a means of executing code on the RHS of the s/// operator, without jumping through that hoop. Dave	[reply]
Re^3: using functions within regex by jpl (Monk) on May 04, 2011 at 11:48 UTC
Not so perfect, in any event. Here's a snippet of a debugging session `DB<1> $t = 'teach an old dog new tricks' DB<2> $t =~ s/(dog)/@{[ reverse($1) ]}/g DB<3> x $t 0 'teach an old dog new tricks'` [download] You'd have to do `$t =~ s/(dog)/@{[ scalar(reverse($1)) ]}/g` [download]	[reply] [d/l] [select]