Well, not much, but here goes for anyone who has a lot of time to figure this one out--not so much for its complexity, but perhaps its scale.
$_ = sin cos uc lc lstat open mine;
s&\.&&&&s&0&&&&s&1&9&&&s&0(?=7)&8&&&s&$&4&;
s&..&$..=$\&⪚split /(..)/;
map{$a[$b++]=chr(oct(ord(chr($_+$_[$_-1]-$_[$_-2]))))}@_;
$_=$a[0].$a[-4];$c=sub{eval"$_[0]$_[1]$_[2]"};$x=chr &$c($],$_,4);
@_ = map {chr $_%100+50} &$c($#SIG,$_,3)..&$c(294,$_,2);
$_ = [[[[1132],[1175],[1173],[1174],[","]],[[23],[468],
[469],[474],[462],[459],[472],[","]],[['-'],[359],
[572],[566],[","]],[[30],[455],[457],
[465],[459],[572],[","]]]];
map{map{map{map{
print$_[$_]unless((/-/&&print$x)||(/,/&&print' '))
}@$_}@$_}@$_}@$_;