Re: Backticks to capture umask output

There is no umask executable.

$ perl -E'say `umask` // ( $! != -1 ? $! : sprintf("\$?=%04x", $?) );'
No such file or directory
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You are trying to execute a bourne shell command without involving a bourne shell. So invoke the shell:

$ perl -E'say `/bin/sh -c umask` // ( $! != -1 ? $! : sprintf("\$?=%04
+x", $?) );'
0077
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Of course, you should just use the builtin umask.

$ perl -E'my $umask = umask; say defined($umask) ? sprintf("%04o", $um
+ask) : $!;'
0077
[download]

Comment on Re: Backticks to capture umask output Select or Download Code

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Re^2: Backticks to capture umask output by austin43 (Acolyte) on May 24, 2011 at 20:58 UTC
Nevermind I get what you're saying. I tried invoking /bin/sh and it worked! Thanks alot.	[reply]
Re^2: Backticks to capture umask output by austin43 (Acolyte) on May 24, 2011 at 20:56 UTC
When I type 'umask' into the terminal (using bash) it outputs 0037 though...	[reply]
Re^3: Backticks to capture umask output by ikegami (Patriarch) on May 24, 2011 at 20:59 UTC
So use «`/bin/bash -c umask`» instead of «`/bin/sh -c umask`»	[reply] [d/l] [select]
Re^3: Backticks to capture umask output by ikegami (Patriarch) on May 24, 2011 at 20:58 UTC
Yes, but what's your point?	[reply]