in reply to Re^3: (almost) foldl
in thread (almost) foldl

Ok, ok, I'm quibbling.

Then add a couple of extra spaces :) 

say eval join' + ','1e',6;

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Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.

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Re^5: (almost) foldl
by Grimy (Pilgrim) on Jun 08, 2011 at 21:28 UTC
    print eval join' + ','1e',6;

    Bareword found where operator expected at (eval 1) line 1, near "1e" (Missing operator before e?)

    Did this actually test it, or is it because I'm running Perl 5?

    Anyway, print eval join'+0+','1e',6; works okay. Plus, the "+0+" looks nice.

[reply]
[d/l]
[select]

      The point is that '1e' is not a valid number in Perl, so your answer of 7 is at best flawed. 

      C:\test>perl -Mstrict -wE"say 0+'1e'"
Argument "1e" isn't numeric in addition (+) at -e line 1.
1

      [download]
      Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
      "Science is about questioning the status quo. Questioning authority".
      In the absence of evidence, opinion is indistinguishable from prejudice.
[reply]
[d/l]
        Never mind. You're right.
[reply]

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