in reply to Square Root algorithm

I could be misinterpreting the Square Root line here, but this does the trick for me...
$a=25; $b=$a**(1/2); # 25^0.5 print $b; # 5
or with 2
$a=2; $b=$a**(1/2); #2^0.5 print $b; #1.4142135623731
Greetz
Beatnik
... Quidquid perl dictum sit, altum viditur.