Re: Sorting hash of hash of hash by values

You don't seem to be far off, but I hope you didn't fall into the trap of trying to sort the hash itself. Hashes can't be sorted, but arrays or lists made from their keys.

foreach $batch ( keys %{$hash{$host}} ) {
   my @runs= keys %{$hash{$host}{$batch};
   @runs= sort { $hash{$host}{$batch}{$a}{start} <=> $hash{$host}{$bat
+ch}{$b}{start} } @runs;
   foreach $run (@runs) {
      ...
[download]

Naturally you can compress this into one line and remove the need for @runs, but I wanted to show explicitly what I was doing

Oh and it is untested. Wouldn't suprise me if I had made a silly mistake somewhere

Comment on Re: Sorting hash of hash of hash by values Download Code

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Re^2: Sorting hash of hash of hash by values by legendx (Acolyte) on Jul 07, 2011 at 21:45 UTC
Hey thanks! that worked. I was able to sort by the $batch 'duration' values I was using `sort { $hash{$host}{$batch}{$run}{$a}{start} <=> $hash{$host}{$batch}{$run}{$b}{start} }` instead and it wasn't working. Why does `hash{$host}{$batch}{$a}{start} <=> $hash{$host}{$batch}{$b}{start}` work when I am not specifying the $run? Is it because Perl puts the two elements it wants to compare (which is the $run) into the special variables $a and $b?	[reply] [d/l] [select]
Re^3: Sorting hash of hash of hash by values by jethro (Monsignor) on Jul 08, 2011 at 08:56 UTC
Yes, $a and $b are aliases to values that get compared. Even if it were not it wouldn't make sense to add more dereferencing to a hash structure than there is depth. Just out of curiosity: Why did you write $a and $b into your code if you didn't know that?	[reply]
Re^4: Sorting hash of hash of hash by values by legendx (Acolyte) on Jul 08, 2011 at 14:47 UTC
I guess I was not 100% clear on how it worked	[reply]