in reply to Re^3: hash to differentiate type and tokens
in thread hash to differentiate type and tokens

Hi,
#! /usr/bin/perl use strict; use warnings; my $str1='It is a guide to action which ensures that the military alw +ays obey the commands of the party.'; chomp($str1); my $str2='It is a guide to action that ensures that the military will +forever heed Party commands is a guide.'; chomp($str2); my @arr1=split(/\s+/, $str1); my $n_occur_in_str1=0; my $n_occur_in_str2=0; print "-"x60,"\n"; print "nth Match\tNo of occurence\t\tMatched Pattern\n"; print "-"x60,"\n"; for(my $i=0; $i<$#arr1;$i++) { my $t1="$arr1[$i] $arr1[$i+1] $arr1[$i+2]"; my @pattern_word_count=split(/\s/, $t1); my $space_count=@pattern_word_count; if($space_count == 3) { if($str2=~/$t1/) { my $occurence=`echo $str2 | grep -o '$t1' |wc - +l`; chomp($occurence); print $i+1,"\t\t",$occurence,"\t\t\t$t1\n"; $n_occur_in_str2+=$occurence; $n_occur_in_str1++; } } } print "\n\nTotal no of occurence in str1 : $n_occur_in_str1\n"; print "\n\nTotal no of occurence in str2 : $n_occur_in_str2\n";

in the above code i used an array to store the splitted words from sentence and then use each words for further processing

Here, the problem is when i have repeated words, unwantedly i do computation for same words. so to avoid tat i have been advised to store the words in a hash rather than an array.

But, i m not clear how i can do that

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Re^5: hash to differentiate type and tokens
by Anonymous Monk on Jul 13, 2011 at 12:10 UTC

    in the above code i used an array to store the splitted wor

    Oh, now I remember, this is Comparison between keys in hash all over again

    Ask yourself why anyone would help someone who 1) ignores their advice 2) ignores their questions 3) repeat the same thing, repeatedly?

    I tried to help you before, but every time its either like pulling teeth or like talking to a wall

      Hi Anonymous Monk,

      Sorry, if i did anything wrong. I dint repeat the question. what i was saying is, i just want to know that it is possible to replace the array by hash to avoid duplication. thats all

      Thanks for the advise. I will try it.