in reply to find weekdays for a year
For future reference you should show the things that you have tried. We aren't a code-writing service.
That being said you should look at Date::Simple. What you want to do is find the first thursday of a year. Date::Simple uses Sunday as the 0th day of the week so Thurs is the 4th. I used Date::Calc because it was on my computer already.
use Date::Calc qw(:all); $count = 0; #insert your own year. $year = "2011"; #set $date to the first day of the year @date = ($year,1,1); print Date_to_Text(@date) . "\n"; #find the next thursday if(Day_of_Week(@date) > 4) { @date= Add_Delta_Days(@date,7-Day_of_Week(@date)+4); } else { @date=Add_Delta_Days(@date,4-Day_of_Week(@date)); } #now you have the first thursday. Now just count how many #until you reach a new year while(@date[0] eq $year) { $count++; @date=Add_Delta_Days(@date,7); } print "$count thursdays in $year\n";
You should probably verify that the results are correct. They seem to make sense to me but that doesn't mean much. Hope this helps.
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Re^2: find weekdays for a year
by fionbarr (Friar) on Jul 19, 2011 at 13:51 UTC | |
by Anonymous Monk on Jul 19, 2011 at 13:59 UTC |