in reply to still confused with CGI and carriage returns carriage returns

(Okay I wrote then when I must have been on crack, its wrong, so see the replies ...)

Original text:
Your problem is the$description =~ tr/\n/ /; You should use: $description =~ s/\n/ /g; I think tr/// treats the "\n" liternally as a "\" and "n", while the s/// will treat it as a metacharacter.

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RE: Re: still confused with CGI and carriage returns carriage returns
by chromatic (Archbishop) on Apr 26, 2000 at 19:31 UTC
    It works for me: 
    my $string = "hi, \n\nhow are you\n?";
$string =~ tr/\n/X/;
print ">>$string<<\n";

    [download]
    Result: >>hi, XXhow are youX?<<
[reply]
[d/l]
      Okay so I am an ass yet again. I did try it on my system before I rambled and the tr did not work, so I must have had a dumb little typo.

      Just for kicks I benchmarked the s/// vs tr/// since they seem to do the same in this reguard: 
      use Benchmark;
$str = "\n#\n#\nSTUFF\n#\n#\n";
timethese(1000000, {
        's' => sub { $a = $str; $a=~s/\n/ /g; },
        'tr' => sub { $a = $str; $a=~tr/\n/ /; }
});

RESULTS:

Benchmark: timing 1000000 iterations of s, tr...
         s: 11 wallclock secs (11.22 usr +  0.00 sys = 11.22 CPU)
        tr:  3 wallclock secs ( 3.61 usr +  0.00 sys =  3.61 CPU)

      [download]
      The moral of the story: Use tr/// where you can.
[reply]
[d/l]

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