Re^2: Invalid Hex Conversion?

I increment $Address in the second line of the for loop with $Address++. Is this an improper way to do this? Because the script works fine, up to the point where you pass it a character, then it produces the bug I described.

Comment on Re^2: Invalid Hex Conversion?

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Re^3: Invalid Hex Conversion? by SuicideJunkie (Vicar) on Jul 21, 2011 at 19:03 UTC
Incrementing is magical, but not THAT magical :) There is no way to tell if you want the increment to change "19" into "1A" rather than "20", for example. Use `$value = hex($string)` to get a regular number before you apply math to it.	[reply] [d/l]
Re^4: Invalid Hex Conversion? by tfredett (Sexton) on Jul 21, 2011 at 19:23 UTC
Thanks to everyone, it was indeed that I hadn't converted it from a string to a regular number before the applying the necessary math to it. Thanks guys!	[reply]