Hello all. I'm new to Perl, and really new to programming in general - I'm an sysadmin by trade (please don't hold that against me). Inspired by the Hanoi towers node, I wrote this as an learning exercise on recursive subroutines.
It's really a simple function, it prompts you for n, and then calculates (x + y)^n and expands it out as you would in an algebra 101 class, using binomial theorem. I welcome any comments, suggestions or opinions. I'd like to know if there's a better way to format the output other than running it through a bunch of regex's. I know it's not the prettiest code, but bear with me:
#!/usr/bin/perl use strict; use warnings; my ($power, $result); sub binomial_power { my ($c, $xp, $yp) = @_; $result .= $c . "x^" . $xp . "y^" . ($yp - 1) . " + "; if ($yp <= $power ) { binomial_power ((($c * $xp)/$yp), ($xp-1), ( +$yp+1));} } # Get the input print "\nEnter the power: "; chomp($power = (<STDIN>)); # Do the work binomial_power (1, $power, 1); # Make it pretty $result =~ s/1x/x/g; $result =~ s/x\^1/x/g; $result =~ s/y\^1/y/g; $result =~ s/x\^0//g; $result =~ s/y\^0//g; # And print it out print "The result is: \n(x + y)^$power = $result\n";
For reference - $c is the coefficient, $xp is the exponent of x, and $yp is the exponent of y
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Re: Algebraic Expansion of Binomials Using a Recursive Subroutine
by toolic (Bishop) on Jul 28, 2011 at 14:39 UTC | |
by Jim (Curate) on Jul 31, 2011 at 04:03 UTC | |
by Jim (Curate) on Jul 31, 2011 at 00:44 UTC | |
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Re: Algebraic Expansion of Binomials Using a Recursive Subroutine
by ambrus (Abbot) on Jul 29, 2011 at 12:25 UTC |