Re: LSB to MSB

Have a hex value of 6bf 0110 | 1011 | 1111

What you really have is

6b f0
[download]

I've looked at "pack/unpack" but cannot figure it out.

Show your efforts. Usually, pack/unpack aren't used for flipping bits, you use & or | for that, see perlop

Your title hints what you really are talking about is

$ perl -le " print unpack 'H*', pack 'h*', '6bf';
b60f
[download]

$ perl -le " print join ' ', split /(....)/, unpack 'b*', pack 'h*', '
+6bf';
 0110  1101  1111  0000

$ perl -le " print join ' ', split /(....)/, unpack 'B*', pack 'h*', '
+6bf';
 1011  0110  0000  1111
[download]

Comment on Re: LSB to MSB Select or Download Code

Replies are listed 'Best First'.
Re^2: LSB to MSB by Eliya (Vicar) on Aug 07, 2011 at 07:17 UTC
What you really have is `6b f0` [download] Why? Normally, you can leave off leading zeros, i.e. `0x6bf` is the same as `0x06bf` or `0x000006bf`. `0x6bf0` is a different value, though: `$ perl -le 'print 0x6bf' 1727 $ perl -le 'print 0x6bf0' 27632` [download]	[reply] [d/l] [select]
Re^3: LSB to MSB by Anonymous Monk on Aug 07, 2011 at 07:57 UTC
Why?... Thanks You can see from my code examples why I thought so, pack doesn't assume leading 0, and I did not make the integer connection	[reply]