in reply to Re^3: best sort
in thread best sort
If those were the things I was looking into, I would certainly not want a bare sort for any of them.
If you anticipate repeated elements, you'd probably want a tie-breaking
(the bare sort comparison function) on all but the first, because non-identical terms can otherwise compare equal and identical elements may not be adjacent in the sorted output. But I think we are in fundamental agreement: You need to know what you are comparing and how. That may be easier said than done. Knowing that "machenry" is a Scottish name, but "machinery" is not (or is it, and, if not, why not) makes "knowing what you are comparing" non-trivial.$a cmp $b
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Re^5: best sort
by tchrist (Pilgrim) on Aug 16, 2011 at 17:30 UTC | |
by jpl (Monk) on Aug 16, 2011 at 18:36 UTC |