in reply to Re: Re: What's like $+ but not gives the ordinal?
in thread What's like $+ but not gives the ordinal?

That's not very Perlish. I agree it can save some accidents, but really, on subtraction? And why just use scalar on one of the operands of -, and not the other? Wouldn't 
    scalar ($sub [scalar (scalar (@-) - scalar (2))]) -> ()

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be more "always use scalar rather than implying it" then just using it once? Or do you perhaps mean you only use it sometimes?

-- Abigail

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Re: Re: What's like $+ but not gives the ordinal?
by chipmunk (Parson) on Jun 28, 2001 at 06:29 UTC
    Presumably, John meant that he always uses scalar on arrays (when they're in scalar context, of course). This implicit meaning in John's sentence is much like the implicit scalar on arrays in scalar context; if John had been explicit, you would not have been confused. ;)
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