Re^3: Another regex to solve ...

but it's not even remotely elegant. I'll keep working on it.

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Re^4: Another regex to solve ... by pat_mc (Pilgrim) on Aug 18, 2011 at 16:50 UTC
Hm ... yes, of course ... the explicit disjunction would work. I guess we both agree on the elegance of this solution (or lack thereof) ;-) Thanks for posting it, nonetheless!	[reply]
Re^5: Another regex to solve ... by AR (Friar) on Aug 18, 2011 at 16:58 UTC
Two regexes work: `$w =~ /([aeiou])p\b/ && $w !~ /${1}${1}p\b/`	[reply] [d/l]