Re^4: Why doesn't SUPER cause dead loop here?

You're say you think it's defined, but the only thing you gave to back that up is that other things aren't defined. Please show where it is defined if it is.

...As you can see, there's no mention of operand evaluation order.

And despite this, you understand the left hand side has to be evaluated before the right

I really don't care if/where it is documented, it has been used this way since there was a perl5, in core modules since at least perl-5.002, 15 years ago, and in perltoot since about perl-5.004, 14 years ago

Comment on Re^4: Why doesn't SUPER cause dead loop here?

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Re^5: Why doesn't SUPER cause dead loop here? by ikegami (Patriarch) on Sep 02, 2011 at 08:22 UTC
Did you read what you linked to? And despite this, you understand the left hand side has to be evaluated before the right Quite the opposite, I understand the this isn't true at all. Perl is free to place the contents of `@_` on the stack before evaluating the `shift(@_)`. There's nothing in the linked post to support your statement. It states what Perl does, not what Perl must do. In fact, it contradicts your statement because it specifically points out that other behaviours are possible. and in perltoot since about perl-5.004, 14 years ago uh, nowhere in perltoot or in the other document you linked is `@_` both used and modified in the same statement, much less the more specific `shift->foo(@_)`. In case there's any confusion, `shift->foo()` and `$class->foo(@_)` are perfectly safe, it's `shift->foo(@_)` that's not.	[reply] [d/l] [select]
Re^6: Why doesn't SUPER cause dead loop here? by Anonymous Monk on Sep 02, 2011 at 09:07 UTC
Did you read what you linked to? Yes , did you? In case there's any confusion, shift->foo() and $class->foo(@_) are perfectly safe, it's shift->foo(@_) that's not. And still, its used all over CORE	[reply]
Re^7: Why doesn't SUPER cause dead loop here? by ikegami (Patriarch) on Sep 02, 2011 at 09:37 UTC
Yes , did you? Yes. There's nothing in the linked post to support your false that Perl must execute the `shift(@_)` before the `@_` on the right. Nowhere in perltoot or in the other document you linked is `@_` both used and modified in the same statement. None of the three links show what you claimed they do. And still, its used all over CORE Thank you. This is all I asked for. So much code using that undocumented behaviour means it's not likely to change, at least not without a good long deprecation cycle.	[reply] [d/l] [select]