Re^2: Hashes and Memory

Does it copy the hash? I'm still rather new at perl (just 1 year experience). This could mostly likely be a novice error.

How does your code work? my @c = split /\s+/,$ref_coord->{$id};

Does it create an array based on the space between the coordinates in the hash value? and what does the "->" mean exactly?

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Re^3: Hashes and Memory by Jeri (Scribe) on Sep 08, 2011 at 17:37 UTC
Actually, I understand it. My question is how can I put the coordinates in @c if the hash has not been dereferenced? or am I doing (and thinking) about this all wrong?	[reply]
Re^4: Hashes and Memory by Kc12349 (Monk) on Sep 08, 2011 at 18:13 UTC
You don't need to dereference the hash ref into a standard hash variable to use it. As the previous poster said, this will make a copy of the hash instead of editing the original. You can use a hash ref just as you would a standard hash by dereferencing as needed. Below are comparisons of some common hash syntax. `Hash Hash Ref my %hash = (key=>'value'); my $hash_ref = {key=>'value'}; $hash{key} = 'mod_value'; $hash_ref->{key} = 'mod_value'; print $hash{key}; print $hash_ref->{key}; my @keys = keys %hash; my @keys = keys %{$hash_ref};` [download]	[reply] [d/l]
Re^4: Hashes and Memory by RichardK (Parson) on Sep 09, 2011 at 09:37 UTC
Have a look at perlreftut for the tutorial on references. That should tell you everything you need to know :)	[reply]
Re^4: Hashes and Memory by Jeri (Scribe) on Sep 09, 2011 at 15:46 UTC
Got everything working! Thanks Everyone!	[reply]