Re^3: Regex: return the pattern instead of the actual match

Replies are listed 'Best First'.
Re^4: Regex: return the pattern instead of the actual match by JavaFan (Canon) on Sep 16, 2011 at 14:17 UTC
Really? How does that work? How do you re-construct the subpattern from the (not necessarely unique) label you've given it? And why can't you do the same magical trick with the unique numbered match?	[reply]
Re^5: Regex: return the pattern instead of the actual match by LanX (Saint) on Sep 16, 2011 at 14:40 UTC
>Really? How does that work? Re: Regex: return the pattern instead of the actual match > And why can't you do the same magical trick with the unique numbered match? you might need other groupings which are not necessarily interesting. The template system I used offers full flexibility. If you wanna do this with numbered matches you need to parse the template. Cheers Rolf	[reply]
Re^6: Regex: return the pattern instead of the actual match by JavaFan (Canon) on Sep 16, 2011 at 16:00 UTC
Oh, sure, that works. But that isn't very much different from using: `/(foo\d+)\|(bar\S+?)/` [download] and checking which of $1 or $2 is defined. It requires some out-of-bound data that maps to capture group identifier to sub-pattern, and this out-of-bound data needs to be set up when creating the pattern (you can't use this trick if the pattern is given, unless you deconstruct and reconstruct the pattern). And then, instead of using captures, one may use marks: `/foo\d+(:foo)\|bar\S+(:bar)/` [download] and consult $REGMARK afterwards.	[reply] [d/l] [select]
Re^7: Regex: return the pattern instead of the actual match by LanX (Saint) on Sep 17, 2011 at 12:17 UTC