Re: why do I have to provide context to split result in a separate statement?

\(@arr = split / /, '') returns a list of references.

For example \( $a, $b, $c ) is actually ( \$a, \$b, \$c ) and you can't dereference that as an array.

What you could do is copy the list to an anonymous array:

print @{[@arr = split / /, '']}
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Re^2: why do I have to provide context to split result in a separate statement? by ikegami (Patriarch) on Sep 21, 2011 at 01:43 UTC
Don't need to copy it into two arrays. `print @{[ split / /, '' ]}` [download]	[reply] [d/l]
Re^3: why do I have to provide context to split result in a separate statement? by Mark_Galeck (Novice) on Sep 21, 2011 at 02:04 UTC
Thank you very much!	[reply]
Re^3: why do I have to provide context to split result in a separate statement? by jwkrahn (Abbot) on Sep 21, 2011 at 01:59 UTC
Tell that to Mark_Galeck `:-)`	[reply] [d/l]
Re^4: why do I have to provide context to split result in a separate statement? by ikegami (Patriarch) on Sep 21, 2011 at 02:11 UTC
Only your code does that, not his.	[reply]