in reply to code for review
An obvious mistake
###### OUT PATH DETAILS ######$jnl=$ARGV[0];should be
###### OUT PATH DETAILS ###### $jnl=$ARGV[0];
But don't do this, better
my ($jnl,$artno,$outpath,$proftxt)=@_;instead
my $jnl; my $artno; my $outpath; my proftxt; $jnl=$ARGV[0]; $artno=$ARGV[1]; $outpath=$ARGV[2]; $proftxt=$ARGV[3];
What's the purpose of your code?
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