dbarstis has asked for the wisdom of the Perl Monks concerning the following question:
I need to send an encrypted code to a web server where it will be decrypted with a java script. I have a script that creates the token and another that can decrypt it. The problem is when I send it to the java script, it throws an exception because of the padding. PKCS#5 pads with the number of bytes that should be truncated. So, if blocksize is 8, then "0A0B0C" will be padded with "05", resulting in "0A0B0C0505050505". If the final block is a full block of 8 bytes, then a whole block of "0808080808080808" is appended. In my script I can pad with nulls but how would I do PKCS#5? If someone could rewrite this (even using Crypt::CBC) and get the 32 character token with the correct padding, I would be forever grateful
In my haste to post the code, I didn't complete the scrubbing. I've made the corrections.
#!/usr/bin/perl use Crypt::Rijndael; my $key = "1A2B3C4D5E6FA1B2C3D4E5F61A2B3C4D"; $key = pack("H*",$key); $crypt = Crypt::Rijndael->new( $key, Crypt::Rijndael::MODE_ECB() ); my $vers = 1; my $rand = 1002247; my $time = 1317072992; my $empid = 123; my $sum = 103; $packed = pack( "CLLLC", $vers, $rand, $time, $empid, $sum ); my $token = $crypt->encrypt($packed^("\0"x16)); $token = unpack("H*",$token); print "---------+---------+---------+--\n"; print $token,"\n"; exit;
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: AES/ECB/PKCS#5 encryption
by zentara (Cardinal) on Sep 29, 2011 at 08:16 UTC | |
|
Re: AES/ECB/PKCS#5 encryption
by zentara (Cardinal) on Sep 29, 2011 at 07:49 UTC | |
|
Re: AES/ECB/PKCS#5 encryption
by dbarstis (Novice) on Sep 29, 2011 at 14:05 UTC | |
|
Re: AES/ECB/PKCS#5 encryption
by dbarstis (Novice) on Sep 29, 2011 at 12:29 UTC |