Newbie to PERL debugger

ISAI student has asked for the wisdom of the Perl Monks concerning the following question:

Hello all. I am trying to get the debugger to print out variable values based on pattern and fail miseraly. See sample code below:

#!/usr/bin/perl -w
use strict;
my $m=0;
my $popop=1;
$popop=2;
__END__
[download]

I run the debugger, do b 5, and can't find the vraiable $popop. See code below:

perl -d ./converCshelltsetenvToSkill.pl

Loading DB routines from perl5db.pl version 1.28
Editor support available.

Enter h or `h h' for help, or `man perldebug' for more help.

main::(./converCshelltsetenvToSkill.pl:3):
3:      my $m=0;
  DB<1> b 5
  DB<2> c
main::(./converCshelltsetenvToSkill.pl:5):
5:      $popop=2;
6:      __END__
  DB<2> X *popo*
  DB<3>
[download]

What am I doing wrong here?

Comment on Newbie to PERL debugger Select or Download Code

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Re: Newbie to PERL debugger by runrig (Abbot) on Oct 05, 2011 at 15:19 UTC
The docs say to use "~" for regexes with V and X, so you want: `X ~popo` [download]	[reply] [d/l]
Re^2: Newbie to PERL debugger by ISAI student (Scribe) on Oct 05, 2011 at 15:49 UTC
No luck there either. `DB<6> X ~popo DB<7>` [download]	[reply] [d/l]
Re^3: Newbie to PERL debugger by runrig (Abbot) on Oct 05, 2011 at 15:57 UTC
Ah, X and V are only for package variables. They will not work for lexical (my) variables. You can display specific lexical variables with "x", but not by regex. It does say "y" should work for lexicals like V and X, if you have PadWalker installed (which I don't).	[reply]